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Complete each step of the factorization of the trinomial by grouping.$$\begin{aligned}35 t^{2}-11 t-6 &=35 t^{2}+10 t-21 t-6 \\&=5 t(7 t+2) \_ 3(7 t+2) \\&=(\quad)(5 t-3)\end{aligned}$$
$(7 t+2) \quad(5 t-3)$
Algebra
Chapter 6
Factoring and Quadratic Equations
Section 3
Factoring Trinomials of the Form $a x^{2}+b x+c 454$
Equations and Inequalities
Quadratic Functions
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Okay, So as to completely fallen characterization. So we have our training. We'll split up into two turns up t so 10 t and 21 team and I we're gonna factor by grouping. So we're gonna group these two terms and these details so already grouped our 1st 2 terms. So we're only looking at our last in terms. So it seems like going from the top to the bottom that we factored out of three as well as a negative signed and then we could see that's cracked. Because when we factor out are like terms 17th us. Do you see that we have a five t I want us to be remaining that we have here, and then we're this left off a 72.
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