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Complete each table. See Example 11.$$\begin{array}{|c|c|}\hline x & {\frac{1}{x+8}} \\\hline-7 & {} \\\hline-9 & {} \\\hline-8 & {} \\\hline\end{array}$$
a. $x-19$b. 19
Algebra
Chapter 1
An Introduction to Algebra
Section 8
Algebraic Expressions
The Language of Algebra
Equations and Inequalities
Functions
Linear Functions
Quadratic Functions
Polynomials
Campbell University
McMaster University
Harvey Mudd College
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So here we have three blinks on the function is one over X plus eight. So if we plug in negative seven first one over negative seven plus eight was 1/1 close one. The 2nd 1 is negative. One over negative nine plus eight is equal to one over negative one secrets in 81 and last, but not least one over native eight plus eight is equal to 1/0. If you actually listen to your calculator, it's undefined because nothing can be divided by zero is undefined.
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