00:01
Okay, so in this problem, a square with vertices a equals 11, b equals 04, c equals 35, and d equals 4 ,2 is reflected over the x -axis to produce a new square with vertices a prime, b prime, c prime, d prime, find the area of a square a -prime b -priam b -priam, and b find in y form the equation of ac.
00:25
So first we'll start off with the vertices.
00:28
So the vertices.
00:30
So to calculate a, we can do square root of 1 minus 0 squared plus negative 1 plus 4 squared.
00:42
So that's going to be 1 plus 9.
00:47
And that's going to be square root 10.
00:50
So to calculate the area, so it's a squared.
00:53
So now to do that, a squared equals area, that means that if you do, let's write that a little bit.
01:05
We do 10, square root of 10, and then we square that.
01:12
We'll get out shorter, square root of 10, and we parentheses square that.
01:20
That means we can just take away the square root.
01:23
So the area is going to equal 10.
01:25
So the reflected square area is equal 10.
01:28
So square area equals 10...