00:01
So the key here is to look at the coefficients that are given in the reaction equation, and that's going to determine what the change is going to be.
00:09
So you want to look at the ratio of what is already assigned as x.
00:15
So in letter a, x is assigned to barium 2 plus.
00:20
So anything in the equation with a 1 in front of it, its change is just going to be 1x.
00:25
Anything that would have a 2 in front of it would be 2x, etc.
00:28
3, 4, 5.
00:30
So that's how to approach these problems.
00:34
So in this case, s .o .4 to minus, basically, it's just going to be 1x because the coefficient here would be 1.
00:42
We just don't write it, and the coefficient here would be 1.
00:46
For part b, sulfate is assigned x...