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Problem 28 Easy Difficulty

Complete the following radioactive decay formulas:
a) $^{12}_{5} \mathbf{B} \rightarrow ?+\mathbf{e}^{-}+\overline{\nu}$
b) $^{234}_(90) \mathrm{Th} \rightarrow_{88}^{230} \mathrm{Ra}+?$
c) $? \rightarrow^{14}_{7} \mathrm{N}+\mathrm{e}^{-}+\overline{\nu}$

Answer

a. _{5}^{12} B \rightarrow_{6}^{12} C+_{-1}^{0} e+\nu
b. _{90}^{234} T h \rightarrow_{88}^{230} R a+_{2}^{4} H e
c. no answer available

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Top Physics 103 Educators
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Liev B.

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Marshall S.

University of Washington

Farnaz M.

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Meghan M.

McMaster University

Video Transcript

from over 28 were supposed to complete each one of these equations. So here you're tired. I'm gonna have beta decay and invaded. Okay, This electron came from when the neutrons splitting into a proton electron. So the mass number's still the same. So this is still gonna be 12. We can, All right, It's will. You're right. Interested. 12 12 and the It's gonna have one more proton. It'd So this will be six. 12 or six. I look in the periodic table and I see a topic. Number six is carbon. Here, you can tell the only thing that changed. I've got two less protons and for less, um, of total mass number. So to pro towns, this is the nucleus of healing. This is Alfa decay. And then here again, you tell it beta decay and dedicated. This electron came from one of the new transit split into a proton. So this originally had one less protons. And this would be six. But the man's number was the same. Look and appear a table and I see atomic number six is carbon

University of Virginia
Top Physics 103 Educators
LB
Liev B.

Numerade Educator

Marshall S.

University of Washington

Farnaz M.

Other Schools

Meghan M.

McMaster University