Question

Complete the following statements by writing one of these words or phrases in each blank. $$ \begin{array}{ll} \begin{array}{l} \text { activated complex } \\ \text { alternative pathway } \\ \text { balanced } \\ \text { change } \\ \text { close to each other } \\ \text { collide } \end{array} & \begin{array}{l} \text { kilojoules per mole, } \mathrm{kJ} / \mathrm{mol} \\ \text { larger } \\ \text { collision } \end{array} \\ \text { lower activation energy } \\ \text { coefficient } & \text { minimum } \\ \text { disrupts } & \text { moles per liter } \\ \text { endergonic } & \text { more quickly } \\ \text { endergonic reaction } & \text { net } \\ \text { equal } & \text { new bonds } \\ \text { equal to } & \text { no effect } \\ \text { equilibrium constant } & \text { old bonds } \\ \text { exergonic } & \text { orientation } \\ \text { fraction } & \text { phase } \\ \text { greater than } & \text { positive } \\ \text { heterogeneous } & \text { pressures } \\ \text { homogeneous } & \text { products } \\ \text { increases } & \text { reactants } \\ K_P & \text { released } \\ \hline \end{array} $$ Increased temperature increases the rate of both the forward and the reverse reactions, but it increases the rate of the _____________ reaction more than it increases the rate of the _____________ reaction. Therefore, increasing the temperature of a chemical system at equilibrium will disrupt the balance of the forward and reverse rates of reaction and shift the system in the direction of the _____________.

   Complete the following statements by writing one of these words or phrases in each
blank.
$$
\begin{array}{ll}
\begin{array}{l}
\text { activated complex } \\
\text { alternative pathway } \\
\text { balanced } \\
\text { change } \\
\text { close to each other } \\
\text { collide }
\end{array} & \begin{array}{l}
\text { kilojoules per mole, } \mathrm{kJ} / \mathrm{mol} \\
\text { larger } \\
\text { collision }
\end{array} \\
\text { lower activation energy } \\
\text { coefficient } & \text { minimum } \\
\text { disrupts } & \text { moles per liter } \\
\text { endergonic } & \text { more quickly } \\
\text { endergonic reaction } & \text { net } \\
\text { equal } & \text { new bonds } \\
\text { equal to } & \text { no effect } \\
\text { equilibrium constant } & \text { old bonds } \\
\text { exergonic } & \text { orientation } \\
\text { fraction } & \text { phase } \\
\text { greater than } & \text { positive } \\
\text { heterogeneous } & \text { pressures } \\
\text { homogeneous } & \text { products } \\
\text { increases } & \text { reactants } \\
K_P & \text { released } \\
\hline
\end{array}
$$
Increased temperature increases the rate of both the forward and the reverse
reactions, but it increases the rate of the _____________ reaction more than
it increases the rate of the _____________ reaction. Therefore, increasing the
temperature of a chemical system at equilibrium will disrupt the balance of the
forward and reverse rates of reaction and shift the system in the direction of the
_____________.
Show more…
Introduction to Chemistry
Introduction to Chemistry
Bishop 1st Edition
Chapter 16, Problem 28 ↓

Instant Answer

verified

Step 1

When temperature increases, the rate of both forward and reverse reactions increases because molecules have more kinetic energy and collide more frequently.  Show more…

Show all steps

lock
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
Complete the following statements by writing one of these words or phrases in each blank. $$ \begin{array}{ll} \begin{array}{l} \text { activated complex } \\ \text { alternative pathway } \\ \text { balanced } \\ \text { change } \\ \text { close to each other } \\ \text { collide } \end{array} & \begin{array}{l} \text { kilojoules per mole, } \mathrm{kJ} / \mathrm{mol} \\ \text { larger } \\ \text { collision } \end{array} \\ \text { lower activation energy } \\ \text { coefficient } & \text { minimum } \\ \text { disrupts } & \text { moles per liter } \\ \text { endergonic } & \text { more quickly } \\ \text { endergonic reaction } & \text { net } \\ \text { equal } & \text { new bonds } \\ \text { equal to } & \text { no effect } \\ \text { equilibrium constant } & \text { old bonds } \\ \text { exergonic } & \text { orientation } \\ \text { fraction } & \text { phase } \\ \text { greater than } & \text { positive } \\ \text { heterogeneous } & \text { pressures } \\ \text { homogeneous } & \text { products } \\ \text { increases } & \text { reactants } \\ K_P & \text { released } \\ \hline \end{array} $$ Increased temperature increases the rate of both the forward and the reverse reactions, but it increases the rate of the _____________ reaction more than it increases the rate of the _____________ reaction. Therefore, increasing the temperature of a chemical system at equilibrium will disrupt the balance of the forward and reverse rates of reaction and shift the system in the direction of the _____________.
Close icon
Play audio
Feedback
Powered by NumerAI
*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Chemical Equilibrium
Chemical equilibrium occurs when the forward and reverse reactions proceed at the same rate, resulting in constant concentrations of reactants and products. This concept is foundational for understanding how systems respond to disturbances, such as changes in temperature, and how shifts in equilibrium occur to re-establish balance in the reaction rates.
Reaction Kinetics
Reaction kinetics involves the study of the rates at which chemical reactions occur and the factors that affect these rates, including temperature and activation energy. Understanding kinetics is crucial for analyzing how changes in conditions alter the speed of both forward and reverse reactions in a chemical system.
Effect of Temperature on Reaction Rate
Temperature significantly influences reaction rates by increasing the kinetic energy of molecules, which leads to more frequent and energetic collisions. As temperature rises, both the forward and reverse reaction rates increase, although not necessarily to the same extent, depending on the activation energies involved.
Activation Energy and the Arrhenius Equation
Activation energy is the minimum energy required for a reaction to occur, and the Arrhenius equation quantitatively relates the rate constant to temperature and activation energy. A higher activation energy means that a reaction's rate is more sensitive to temperature changes, which is key to understanding why one reaction direction might be affected more than the other when temperature is increased.
Le Chatelier's Principle
Le Chatelier's Principle states that if a dynamic equilibrium is disturbed by changing the conditions, the system will adjust itself to partly counteract the change. In the context of temperature changes, this principle helps explain how an equilibrium will shift—toward the endothermic direction if heat is added—to re-establish equilibrium under the new conditions.

*

Recommended Videos

-
question-10-1-point-when-the-temperature-jijin-a-system-in-which-the-forward-reaction-is-f-equilibrium-shifts-toward-ljii-formation-the-statement-given-above-is-completed-by-the-information-08829

When the temperature in a system in which the forward reaction is at equilibrium shifts toward the formation of products, the statement given above is completed by the information provided in the theory. As the temperature increases, the endothermic product increases, the exothermic product decreases, the endothermic reactant decreases, and the exothermic reactant increases.

Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever