Question
Complete the formula-writing exercise in Table 6.14 on page $171 .$ Then test your skill by naming the compounds.$$\mathrm{CuSO}_{4}, \mathrm{Cr}(\mathrm{OH})_{3}, \mathrm{Hg}_{2} \mathrm{I}_{2}$$
Step 1
The charge on the copper ion is +2 and the charge on the sulfate ion is -2. Therefore, the name of this compound is Copper(II) sulfate. Show more…
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