00:01
Let's try this one.
00:02
It says, compose a uniform motion problem that can be solved with a system of equations of your own and shared on discussion board.
00:09
Well, i can't help with the sharing discussion board part, but i can help with creating a uniform motion problem.
00:15
And i made one here.
00:16
A train leaves a station traveling at 45 miles per hour.
00:20
Two hours later, a second train traveling the same direction leaves the station at 50 miles per hour.
00:26
At what distance do the trains travel when the second train catches up to the first? uniform motion means two things traveling at the same time.
00:37
And at what time, at two different times, at what time do they kind of catch up to each other? we got here.
00:43
Uniform motion always goes with distance equals rate times time.
00:48
In this case, we're looking for when the two catch up.
00:52
So the first distance would have to be equal to the second distance.
00:56
And if d equals r times t, then d1 is just r1 and t1.
01:11
T1 and d2 is just r2 and d2.
01:17
Well, we know r1 and r2, those are the rates.
01:20
The rates of the first train was 45 miles per hour.
01:24
Rates of the second train was 50 miles per hour.
01:27
We don't know time, t1 or t2, but we got to write that in terms of a single variable.
01:34
So we'll call the first time x and the second time x minus 2 because the second train left two hours later.
01:45
All right, with that being said, let's plug these numbers into our current equation down here.
01:50
So instead of r1, i now have 45.
01:55
T1 is just x equals r2, which is 50, and t2, x minus 2...