Let $\overrightarrow{\mathbf{u}_1}, \overrightarrow{\mathbf{u}_2} \in \mathbf{U}$. Then,
\begin{align*}
(T \circ S)(\overrightarrow{\mathbf{u}_1} + \overrightarrow{\mathbf{u}_2}) &= T(S(\overrightarrow{\mathbf{u}_1} + \overrightarrow{\mathbf{u}_2})) \\
&=
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