Scandium ion $\mathrm{Sc}^{3+}$ has an electron configuration of [Ar] 4s$^{0}$ 3d$^{0}$, meaning it has no electrons in its d orbitals. On the other hand, Titanium ion $\mathrm{Ti}^{3+}$ and Vanadium ion $\mathrm{V}^{3+}$ have electron configurations of [Ar]
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