00:01
Question is which of the following is not correctly matched here.
00:04
Reaction, reaction intermediate involved.
00:08
Okay, so in the first part we have favoresky rearrangement.
00:12
So carbonyl is formed in this reaction, it is correct.
00:17
Perkin reaction carbogadine.
00:18
No, it is not correct.
00:20
In the perking reaction, carb anine is get formed that is intermediate.
00:26
How? because in the perkin reaction anhydride, hydride is it treated with strong waste like c2h5o minus ne plus.
00:38
This athoxy eliminate this acidic hydrogen and then we will get ch2 minus c double bond ocs3.
00:51
So this is the carb anion that will attack on the benjeldehyde which is used as the reactant in the perkin reaction.
00:58
Right.
01:00
So second option will be incorrect.
01:03
Keylation condensation, carbon is formed.
01:06
Yes, it is correct.
01:08
Because in this reaction, ldhead or ketone is treated with the base.
01:14
So base will abstract acidic hydrogen and carbonine is formed...