00:01
A compressed air is placed in a container that is 0 .041 cubic meter in volume.
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We are to determine the mass density of this compressed air.
00:15
And then letter b, we are to determine the space that it will occupy, had its density be at normal atmospheric pressure, it's just around 1 .2.
00:27
Okay.
00:27
So again, this is a straightforward problem wherein we can own our main working equation is the definition of mass density, which is the ratio of mass to volume of a homogeneous substance.
00:40
So starting with that, that's greek letter row times mass over volume.
00:47
We are to determine, of course, the density.
00:51
So this is already our equation.
00:54
Let's check the units.
00:55
The mass is in mks system.
00:57
And the volume is also in mks system.
01:00
So there's no unit conversion needed.
01:03
So we simply put our value here.
01:05
This is a small container and a lot of air is placed in it.
01:13
So of course, we are expecting here that this density of the compressed air will be much greater than its usual density where it's just unrestrained or uncompressed...