0:00
Hi there.
00:01
So for this problem, we are told that the average range at which the heat flows out through the surface of the earth is a value.
00:13
So that value is the heat over the area, and that value is 54 milliwaps per meter squared.
00:28
And the average thermal conductivity that we denote with the letter key is equal to 2 .5 watts per meter per kelvin.
00:47
And assuming a surface temperature that is equal to 10 celsius degrees, what should be the temperature at a depth that is equal to this change in the depth? is, well we call this change in the depth is equal to 33 kilometers.
01:20
Now what we need to obtain from this is first the change in the temperature and with that value we can obtain the final temperature.
01:41
So we're going to start with the equation for the heat.
01:46
We are told that the heat transfer is equal to the thermal conductivity, okay, times the area, times the change in temperature over the change, in this case of the depth.
02:04
Now, the rate at which the heat flows out is given as a power per area.
02:11
So the quantity given is precisely h over a.
02:18
That is the value given in here, this one right here.
02:23
And the temperature difference, we just need to solve from this equation.
02:30
We will find quite easily that is equal to h over a, heat over the area, times the change in the death over the overt.
02:43
The thermal conductivity.
02:47
So we just need to simply substitute all of these values in here.
02:51
So we will have that this is equal to...