00:01
According to problem number 4, chapter number 14, well, you know, it is easier to use spherical coordinates rather than cylindrical or rectangular coordinates.
00:17
So this solution looks like because long because, you know, i've broken down every step, but it can be computed in just a few lines of the calculation.
00:28
So with spherical coordinates, you know, we can define a sphere radius r by all coordinate points where 0 is less than the end.
00:48
Right.
00:48
So where this is, you know, is the angle measure down from the positive zx and.
00:59
You know zero is less than or equal to and less than or equal to 2.
01:06
Right.
01:07
So just the same as it would be polar coordinates and p is equal to r right.
01:15
So the jacobian for spherical coordinates is given by j is equal to p square sine...