00:01
The relativity kinetic energy is given by k is equal to mc square divided by square root of 1 minus v square divided by c square minus mc square.
00:10
We can shrink this problem, sorry, this equation into gamma minus 1 mc square, by writing a gamma is equal to 1 over 1 minus square root of v squared divided by c square.
00:24
Part a of the problem, using a non -relativistic, non -relativistic, we can write kinetic energy for non -relatistic case.
00:38
That is a 1 over 2 mv square.
00:42
Or we can say the classical, the classical equation for kinetic energy.
00:46
That is only equal to 1 over mv square.
00:49
We substitute the values for mass and v.
00:52
1 .67 times 10 to the power minus 27 is kg is the mass of proton times its speed which is 8 times 10 to the power 7 meter per second this gives us the non -relativistic kinetic energy to be 5 .344 times 10 to the power minus 12 kg meter square per second square.
01:19
Then for relativistic case, using the above equation, we wrote previously, we can write for relativity case, we can write 1 .67 times 10 to the power minus 27 times 3 times 10 to the power 8 square divided by square root of 1 minus 8 times 10 to the power 7 divided by square divided by c square, which is 2.
01:49
3 times 10 to power 8 square minus 1 .67 times 10 to the power minus 27 times 3 times 10 to the power 8 square...