00:01
All right, guys, in order to solve this question, we are given the eutectoid cementite in an iron carbon alloy that contains 0 .87 per 87 percentage by weight of carbon.
00:20
From portion of uh...
00:25
Uh...
00:26
F e dash f e three carbon phase diagram that is uh...
00:34
Referred to figure nine point thirty one of the chapter where we can find that the value of c a is 0 .022 as well as the value of f e 3c the it means three atoms of iron ferric and one atom of carbon is 6 .70 now we use the liver rule in conjunction with a tie line that extends from the phase boundary that is 0 .002 to the eutectoid composition 0 .76 so sorry sorry from the phase boundary, that is 0 .022 to the eutectoid composition, that is 0 .76, in as much as pear light is the transformation product of austinite having composition, having this composition.
01:50
So the mass fraction in solid solution phase is equal to the below formula, that is, is equal to c .a.
02:17
Minus c nod divided by c .a.
02:24
Minus c .f .e .3.
02:31
C.
02:32
Okay.
02:37
Now we put the values and we get w .a.
02:49
Is equal to 0 .022.
02:53
022 minus 0 .87 divided by 0 .022 minus 6 .70...