00:01
Question 45 is asking us to calculate the peak wavelength of a black body whose temperature is 2 .73 kelvin's.
00:10
Now, the way we calculate black body temperatures or black body wavelengths is we use what's called beanslaw, which states that t for temperature is equal to 2 .9 times 10 to the 7.
00:31
It's just shorthand for 2 .9 million nanometers times kelvin's over lambda peak.
00:42
So if we know the wavelength, we can find the temperature and vice versa.
00:48
So here we know what the temperature is.
00:50
We just need to find the peak wavelength.
00:53
Now, all we need to do is just rearrange our formula, and that gives us 2 .9.
01:01
Times 10 to the 6th nanometers times kelvin over 2 .73 kelvin's.
01:12
Now, our kelvin's just cancel out, and what we're left with is our answer in nanometers.
01:19
And that ends up being 1 .06 times 10 to the 6th nanometers...