Question

Computing Grades Going into the final exam, which will count as two tests, Brooke has test scores of 80,83,71,61 , and $95 .$ What score does Brooke need on the final in order to have an average score of $80 ?$

Name: Problem 89, Chapter 1: Algebra and Trigonometry
Uploaded: 2020-04-10T15:14:12-08:00
Duration: 1 min 34 s
Channel: Ankit Gupta
Description: Computing Grades Going into the final exam, which will count as two tests, Brooke has test scores of 80,83,71,61 , and 95 . What score does Brooke need on the final in order to have an average score of 80 ?

   Computing Grades Going into the final exam, which will count as two tests, Brooke has test scores of 80,83,71,61 , and $95 .$ What score does Brooke need on the final in order
to have an average score of $80 ?$

Algebra and Trigonometry

Michael Sullivan 11th Edition

Chapter 1, Problem 89

Instant Answer

Solved by Expert Ankit Gupta

04/10/2020

Step 1

Brooke has already taken 5 tests, and the final exam counts as 2 tests. So, there will be a total of 5 + 2 = 7 tests. Show more…

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Computing Grades Going into the final exam, which will count as two tests, Brooke has test scores of 80,83,71,61 , and $95 .$ What score does Brooke need on the final in order to have an average score of $80 ?$

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Key Concepts

Arithmetic Mean

The arithmetic mean is the sum of a set of values divided by the number of values. It is a commonly used method to compute the average, which in most grading systems represents the overall performance across tests or assignments.

Weighted Average

A weighted average is used when different components contribute differently to the overall result. In grading, if one exam counts more than others—such as a final that counts as two tests—the weighted average accounts for this extra weight, ensuring that each component's impact on the overall score is properly proportioned.

Solving Linear Equations

Solving linear equations involves setting up an algebraic equation based on the given conditions and then isolating the unknown variable. This concept is essential for determining the necessary score on future assessments to reach a desired average.

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