Question
Computing surface areas Find the area of the surface generated when the given curve is revolved about the $x$ -axis.$$y=\frac{x^{4}}{8}+\frac{1}{4 x^{2}} \text { on }[1,2]$$
Step 1
The function is $y=\frac{x^{4}}{8}+\frac{1}{4 x^{2}}$. Using the power rule for differentiation, we get: $$y'=\frac{1}{2}x^{3}-\frac{1}{2x^{3}}$$ Show more…
Show all steps
Your feedback will help us improve your experience
Ethan Feldman and 89 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Computing surface areas Find the area of the surface generated when the given curve is revolved about the $x$ -axis. $$y=\frac{1}{4}\left(e^{2 x}+e^{-2 x}\right) \text { on }[-2,2]$$
Applications of Integration
Surface Area
Computing surface areas Find the area of the surface generated when the given curve is revolved about the given axis. $y=\frac{x^{2}}{4},$ for $2 \leq x \leq 4 ;$ about the $y$ -axis
Computing surface areas Find the area of the surface generated when the given curve is revolved about the $x$ -axis. $$y=x^{3 / 2}-\frac{x^{1 / 2}}{3} \text { on }[1,2]$$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD