00:01
In this problem, you have an aqueous solution of ammonia with a molarity of 14 .8 and a density of 0 .9 grams per cubic centimeter.
00:21
The problem asks you to determine the molality, mole fraction, and weight percent of the ammonia in solution.
00:41
So let's start by finding the molality.
00:44
The molality of nh3 is defined as the moles of solute, which is ammonia, over the kilograms of solvent, which is water.
01:12
So we need to find these two different values from the given information.
01:18
So let's start by using the molarity.
01:20
Our molarity is 14 .8, and that is defined as the moles of solute.
01:34
Nh3 over liters of solution.
01:43
This means that for every one liter of solution, we have 14 .8 moles of nh3.
01:57
To make it easy for ourselves, let's assume that we have one liter of solution so that our moles of ammonia is equal to 14 .8.
02:06
So now we know the first value we need the moles of nh3.
02:11
Now we just need to find the kilograms of water.
02:14
This is a bit more complicated.
02:18
We can use the density to find the mass of the solution and find the mass of water from there.
02:25
So we have one liter of solution and that's going to be equal to 1 ,000 milliliters.
02:37
And we can find the mass of this solution by multiplying by the density, which is 0 .9 grams per every 1 milliliter.
02:51
This means that the mass of the whole solution is 900 grams.
02:57
This this 900 grams is equal to the mass of the nh3 plus the mass of water.
03:18
In order to find the mass of water, we have to subtract the mass of nh3 from the 900 grams.
03:25
We have the moles of nh3 and we can convert this to mass by taking the number of moles, 14 .8, and dividing by, or multiplying by the molar mass of ammonia, which is just 17 .031 grams per mole.
03:48
And when we do that, we find that we have 252 grams of ammonia.
03:56
So now we can find the grams of water...