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Numerade Educator

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Problem 10 Easy Difficulty

Concepts and Vocabulary
$$
\left|\begin{array}{ll}
{-4} & {2} \\
{-5} & {3}
\end{array}\right|
$$

Answer

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Top Algebra 2 Educators
GH
Grace H.

Numerade Educator

Alisa L.

University of Texas at Austin

Shubham P.

University of Washington

Martha R.

Michigan State University

Video Transcript

The determinant of this matrix can be calculated by multiplying the diagonals of the values in this array. And we can see that negative four times three minus negative, five times. Two. Once we find these products, we want to subtract them to find the value of the determinant. So here we have a product of negative 12 minus negative 10. And when we simplify this statement, we get negative 12 plus 10 which gives us a value of negative, too.

SUNY Empire State College
Top Algebra 2 Educators
GH
Grace H.

Numerade Educator

Alisa L.

University of Texas at Austin

Shubham P.

University of Washington

Martha R.

Michigan State University