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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64

Problem 46 Hard Difficulty

Confirm that the results of the example Example 8.7 do conserve momentum in both the $x$ - and $y$ -directions.

Answer

$p _ { \mathrm { ix } } = p _ { \mathrm { fx } } = 0.500 \mathrm { kg } \mathrm { ms } ^ { - 1 }$ and $p _ { \mathrm { iy } } = p _ { \mathrm { fy } } = 0.00 \mathrm { kg } \mathrm { ms } ^ { - 1 }$

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Physics 101 Mechanics

College Physics for AP® Courses

Chapter 8

Linear Momentum and Collisions

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Moment, Impulse, and Collisions

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Watch More Solved Questions in Chapter 8

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58
Problem 59
Problem 60
Problem 61
Problem 62
Problem 63
Problem 64

Video Transcript

in this problem, we're asked to comm prove that Mo mentum is conserved in both the X and Y direction from example seventh. So in example seven It talks about a mess, traveling at two meters per second that has a mass of 0.25 kilograms that goes into her room and hits another mouse that is at rest. That's my initial and then afterwards my 0.25 kilogram mass goes off with a 1.5 meters per second velocity at an angle of 45 degrees, and then the other mouse goes off at an angle of 312 degrees. And it's determined in the problem that experience is a velocity of 0.8 six meters per second, so we can calculate our moment at the beginning. So in this case, our moment in the UAE direction is zero because nobody's moving in the right direction and then for our momentum of the ex direction. That's just the momentum of the first object. So that 0.25 times two gives Ms gives us a mo mentum of 0.5 kilograms meters per second in the extraction at the beginning, so if we look at the ex direction in the after our momentum in the ex direction is going to be this component of momentum for one object and this component of momentum for the other object added together. So we should get 0.25 is our mess. Our velocity in the ex direction is the co sign data. So this is 1.5 co sign of 45 plus the momentum of this component which is the mass 0.4 times our velocity, which is also be coastline data. So this is 0.8 86 co sign of 312th and that gives us a total momentum. Is there a 0.5 kilograms Meters per second now in the wind direction This component and this component need to combine to give me zero. Since we had zero initial momentum Envy Why direction? So same idea. We get 0.25 1.5 sign of 45 plus 0.4 times 0.8 86 sign of 312 on this gives me very reckless to zero with are rounded values. So our momentum at the end is equal to our momentum From the beginning

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Irina Lyublinskaya, Gregg Wolfe, Douglas Ingram , Liza Pujji

College Physics for AP® Courses

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Top Physics 101 Mechanics Educators
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