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Confirm that the results of the example Example 8.7 do conserve momentum in both the $x$ - and $y$ -directions.

$p _ { \mathrm { ix } } = p _ { \mathrm { fx } } = 0.500 \mathrm { kg } \mathrm { ms } ^ { - 1 }$ and $p _ { \mathrm { iy } } = p _ { \mathrm { fy } } = 0.00 \mathrm { kg } \mathrm { ms } ^ { - 1 }$

Physics 101 Mechanics

Chapter 8

Linear Momentum and Collisions

Moment, Impulse, and Collisions

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Lectures

04:30

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Multiply. See Example 3 .<…

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$57-58$ Verify that the co…

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Show that the energy-momen…

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Prove the Law of Conservat…

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Multiply. See Example 6

00:37

Multiply. See Example 7.

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Do Exercise 87 if one of t…

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02:02

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03:34

Formulate and prove a gene…

00:35

00:51

in this problem, we're asked to comm prove that Mo mentum is conserved in both the X and Y direction from example seventh. So in example seven It talks about a mess, traveling at two meters per second that has a mass of 0.25 kilograms that goes into her room and hits another mouse that is at rest. That's my initial and then afterwards my 0.25 kilogram mass goes off with a 1.5 meters per second velocity at an angle of 45 degrees, and then the other mouse goes off at an angle of 312 degrees. And it's determined in the problem that experience is a velocity of 0.8 six meters per second, so we can calculate our moment at the beginning. So in this case, our moment in the UAE direction is zero because nobody's moving in the right direction and then for our momentum of the ex direction. That's just the momentum of the first object. So that 0.25 times two gives Ms gives us a mo mentum of 0.5 kilograms meters per second in the extraction at the beginning, so if we look at the ex direction in the after our momentum in the ex direction is going to be this component of momentum for one object and this component of momentum for the other object added together. So we should get 0.25 is our mess. Our velocity in the ex direction is the co sign data. So this is 1.5 co sign of 45 plus the momentum of this component which is the mass 0.4 times our velocity, which is also be coastline data. So this is 0.8 86 co sign of 312th and that gives us a total momentum. Is there a 0.5 kilograms Meters per second now in the wind direction This component and this component need to combine to give me zero. Since we had zero initial momentum Envy Why direction? So same idea. We get 0.25 1.5 sign of 45 plus 0.4 times 0.8 86 sign of 312 on this gives me very reckless to zero with are rounded values. So our momentum at the end is equal to our momentum From the beginning

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