00:01
Hello friends this is the problem based on activity of reductive material activity of reductive material is defined as lambda into n here lambda is decay constant of the sample and is number of reductive nuclei present and decay constant is defined as 0 .693 upon half life so on this concept this problem is based we have to use this concept here it is given sample of 1 kg of uranium in which 0 .72 % is urinium, 0 .05%, 0 .05 % uranium 234 and remaining uranium 238.
01:18
We have to find activity of each isotope be.
01:33
Fraction of each.
01:37
Each isotope with total c -part explain whether the activity of the sample is dangerous or not.
02:12
See here, it is also given half -life of uranium is 2 .44 into 10 to the power 5 here.
02:29
Let us start solving it.
02:32
Mass of uranium 238 in the sample is 0992 .928 in the sample is 0 .992.
02:45
Kg so number of uranium 238 nuclei in the sample mass of uranium 235 upon atomic weight into avogadro number 0 .99286 .023 into 10 to the power 23 upon 0 .23.
03:11
So it is to be 2 .51 into 10 to the power 24 nuclei now, activity of uranium 238 is lambda into an decay constant is 0 .693 upon half life, which is given for uranium 238, 4 .47 10 to the power 9.
03:58
This is half life of uranium 238.
04:02
It is to be used in second.
04:04
So in one year there are 3 .16 into 10 to the power seconds.
04:13
You will get the answer season per second.
04:17
So it is to be converted into curie.
04:26
So you will get 33 into 10 to the power minus 6 curie.
04:33
Or activity of uranium 238 is 33 microcury.
04:52
Now for uranium 235 mass of uranium 235 is 0 .0072 kg.
05:07
So number of uranium 235 nuclei present in the given sample 0 .0072 upon 0 .235 into 6 .023, 10 to the power 23...