Consider a cell based on the following half-reactions:
$$\begin{aligned}\mathrm{Au}^{3+}+3 \mathrm{e}^{-} \longrightarrow \mathrm{Au} & \mathscr{C}^{\circ}=1.50 \mathrm{~V} \\
\mathrm{Fe}^{3+}+\mathrm{e}^{-} \longrightarrow \mathrm{Fe}^{2+} & \mathscr{C}^{\circ}=0.77 \mathrm{~V}
\end{aligned}$$
a. Draw this cell under standard conditions, labeling the anode, the cathode, the direction of electron flow, and the concentrations, as appropriate.
b. When enough $\mathrm{NaCl}(s)$ is added to the compartment containing gold to make the $\left[\mathrm{Cl}^{-}\right]=0.10 M$, the cell potential is observed to be $0.31 \mathrm{~V}$. Assume that $\mathrm{Au}^{3+}$ is reduced and assume that the reaction in the compartment containing gold is
$$\mathrm{Au}^{3+}(a q)+4 \mathrm{Cl}^{-}(a q) \rightleftharpoons \mathrm{AuCl}_{4}^{-}(a q)$$
Calculate the value of $K$ for this reaction at $25^{\circ} \mathrm{C}$.