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Consider a circuit consisting of a lightbulband a capacitor, as shown in circuit 2 of Conceptual Example 24-10. (a) If the frequency of the generator is increased, does theintensity of the lightbulb increase, decrease, or stay the same?(b) Choose the best explanation from among the following:I. As the frequency increases it becomes harder to force current through the capacitor, and therefore the intensity of thelightbulb decreases.II. The intensity of the lightbulb increases because as the frequency becomes higher the capacitor acts more like a shortcircuit, allowing more current to flow.III. The intensity of the lightbulb is independent of frequencybecause the circuit contains a capacitor but not an inductor.

a) see explanationb) see explanation

Physics 102 Electricity and Magnetism

Chapter 24

Alternating-Current Circuits

Current, Resistance, and Electromotive Force

Direct-Current Circuits

Electromagnetic Induction

Alternating Current

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in the first time thing, we have to consider the reactive capacitance off the capacitor, which is given by one divided by the frequency times the capacitance now no silly following. If we increase this frequency, their reactors will decrease. And by decreasing the reactions ah, the capacity behaves more and more like an open circuit. So what happens is that more current who flew through the capacitor and the ball will shine brighter. Because, remember, the bright news off the boat is related to the power that consumes and the power that is consumed by the boat. It's proportional to the square off the current, then more current means more brightness in that light bulb. So again, the intensity of the light both increases as we increase the frequency off the source. Now, for the second item, we have to choose among the options. The better explanation for what you have just explained on the wound. That switch it better is the 2nd 1

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