00:01
In this problem, we're asked, we're told that we have a 10 centimeter by 10 centimeter by 10 centimeter box, so a cube of 10 centimeters on each side.
00:12
It contains 0 .010 moles of nitrogen at 20 degree c, and we want to know what is the rate of collisions and collisions per second on one wall of the box.
00:23
We know that we have this moles, and then we have nitrogen and the temperature, and the volume is 10 to the minus.
00:32
3rd to cubic meters and an area of one side is 10 to the minus 2 square meters.
00:40
So to find the collision rate, we need the velocity in any one direction, we can call it x, which is the, and we need the number density of molecules.
00:57
And so this is the rms velocity divided by squared at 3.
01:02
We need a few things here to calculate.
01:04
To get to this.
01:07
So the rms density, the rms velocity, we know the temperature, we know the bolt in the constant, we know what three is, and we need the mass of a nitrogen molecule.
01:22
And so we know the molecular weight of, in kilograms, of nitrogen is two times 12, two times 14, one nitrogen atom is 14, so 28 times 10 to minus 3, 28 grams.
01:41
And then avogadro's number here is we wind up with 4 .65 times 10 to the minus 26 kilograms is the weight of one nitrogen molecule.
02:00
We have the temperature.
02:01
Now we convert that into kelvin...