Consider a finite Markov chain on $n$ states with stationary distribution $\bar{\pi}$ and transition probabilities $P_{i, j}$. Imagine starting the chain at time 0 and running it for $m$ steps, obtaining the sequence of states $X_{0}, X_{1, \ldots .,} X_{m}$. Consider the states in reverse order, $X_{m}, X_{m-1}, \ldots, X_{0}$.
(a) Argue that given $X_{k+1}$, the state $X_{k}$ is independent of $X_{k+2}, X_{k+3}, \ldots, X_{m} .$ Thus the reverse sequence is Markovian.
(b) Argue that for the reverse sequence, the transition probabilities $Q_{i, j}$ are given by
$$
Q_{i, j}=\frac{\pi_{j} P_{j, i}}{\pi_{i}}
$$
(c) Prove that if the original Markov chain is time reversible, so that $\pi_{i} P_{i, j}=\pi_{j} P_{j, i}$ then $Q_{i, j}=P_{i, j}$. That is, the states follow the same transition probabilities whether viewed in forward order or reverse order.