00:02
This problem covers the concept of the archivist principle and the bianed force and to solve this problem first we need to draw the free body diagram of the block.
00:12
So in the fresh water the forces acting on the block is the weight which is acting vertically downward that is m g and the upward force is the band force that is fp and that is equivalent to the density of the water into the volume of the displaced water into the gravity and acceleration and acceleration.
00:37
Similarly in the sea water the forces acting on the block is the weight that is mg and the vertically upward band force that is equivalent to the density of the sea water into the volume displaced of the sea water into the gravity is an acceleration so for equilibrium the net force along the y direction that is the vertical direction equals zero so, we can write for fresh water, the volume of the displaced water is equivalent to the cross -sectional area, that is this area, a, into the depth below the water surface, that is d1.
01:20
So we can write the density of the fresh water into the cross -sectional area a into d -1 into g -g minus m -g equals 0.
01:35
And similarly, for the sea water, we can write.
01:38
The volume of the displaced water equals the cross -sectional area a into d2 and we can write from the newton second law of motion the density of c into the cross -sectional area a into d2 times g minus m g equals c let's say this is equation one and this is equation two so from one and two we can write the density of the water into the cross -sectional area a into d1 into g is in q were into the density of the c water into the cross -section area a, d2 times g...