00:01
For this problem on the topic of quantum mechanics, we are to consider a potential well defined as it is in the diagram, and we are to consider a particle with mass m and kinetic energy e less than u -0 that is trapped in this well.
00:14
If we are given the boundary condition at the infinite wall, that epsi at 0 is equal to 0, we want to know the form of the function epsi for 0 less than x less than l, and if we are told the we function must remain finite as x approaches infinity, to know the form of the function of x as x is greater than l.
00:36
And then we want to show that the energies of the allowed levels are obtained from solutions of the equations k -kotan k -l is equal to minus kappa.
00:47
Now as with the particle in the box, we have the form of psi, ip -si of x, must equal to a sine kx, where a is constant and k squared is equal to 2m .m.
01:13
Divided by h bar squared.
01:17
Now unlike the particle in a box, however, k and e do not have simple forms.
01:28
Now for part b, if x is greater than l, the wave function must have the form...