00:01
Okay, so here we're giving that the null hypothesis, h0, is mu is equal to 5, and then our alternative hypothesis is that mu is greater than 5.
00:09
So our decision rule here is that x bar minus 5 is over 0 .1 times 416 is greater than 1 .645.
00:19
And then so we, h0 is going to be rejected when, well, x bar is greater than 5 plus 1 .645 times 0 .1 times root 6 .5.
00:30
16, or 4, which is going to be equal here to 5 .041, and we have our sample size and equals 16.
00:38
So here in part a, we have that the population mean is 5 .10.
00:44
Then the probability of a type 2 error can use our formula and get the probability is going to be when z is less than or equal to negative 2 .36, which gives us, 0 .0091.
01:03
So the probability of a type 2 error here is going to be 0 .0091.
01:14
And then to find the population mean is 5 .1, then the power of the test is going to be 0 .9999 .9.
01:34
And in part b, the population mean now is 5 .03.
01:41
So we calculate and we get the probability that z is less than or equal to 0 .44 is going to give us 0 .670.
01:54
And then to calculate the power of a test, so the power of a test is just one minus the probability of the type 2 error.
02:04
So just taking 1 minus the probability, 1 minus 0 .67 is 0 .33...