After the first half of its half-life, the remaining amount of nuclei would be $N_0 \times 0.7071$. This is because the number of remaining nuclei after a half-life is given by $N_0 \times 0.5$, and half of this is $N_0 \times 0.5 \times 0.5 = N_0 \times 0.25 =
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