00:01
In part a, we computed the probability that the sample contains zero white balls, which means all the three drawn give the red balls.
00:16
The probability that the first drawing is the red ball equals 7 or 12, since there are 12 balls and 7 of them are red.
00:28
And then, when red ball is added, so now there are eight red balls and there are 13 balls in total and then another red ball is added.
00:44
Now there are 9 red balls and there are 14 balls in total.
00:51
And hence the probability equals the product of these 3 probability, which equals 3 over 13.
01:00
For parv b, we want to find the probability that a sample contains exactly one white balls.
01:08
So there are three cases.
01:10
The white ball is drawn.
01:13
The first time, there are five white balls and 12 balls in total.
01:21
And then one white ball is added.
01:25
For the second drawing, it's a red ball.
01:28
There are seven red balls and 13 balls in total.
01:34
And now a red ball is added.
01:37
So for the third time, there are three balls.
01:40
8 right balls and 14 balls in total.
01:45
For the second case, we draw the right ball the second time...