00:01
So this question gives us a reaction of a going to products and asks us to write the rate if it's zero order, first order, and second order.
00:30
And so at zero order, rate is equal to k the rate constant times the concentration of a to the zero power.
00:41
And anything to the zero power is one, so the rate is just equal to the rate constant.
00:48
For the first order, rate is equal to k times the concentration of a to the first power, which is just k a, and for second order, rate is equal to k times a squared, and these brackets mean concentration.
01:12
And then it asks what doubling a will do to the rate.
01:18
And so in our zero order, if we double a, it will affect the rate not at all, since our final equation does not include the concentration.
01:32
So for the zero order, doubling the concentration of a, the rate, the rate, stays the same...