Question
Consider a uniform random variable defined on the interval $0 \leq$ $x \leq \beta$, where $\beta$ is unknown. Use the method of moments to find an estimate of $\beta$ based on a given random sample of size $n$.
Step 1
Let \( X \) be a uniform random variable on the interval \( [0, \beta] \). The probability density function (pdf) of \( X \) is given by \( f_X(x) = \frac{1}{\beta} \) for \( 0 \leq x \leq \beta \). Show more…
Show all steps
Your feedback will help us improve your experience
Manik Pulyani and 75 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Let $X_{1}, X_{2}, \ldots, X_{n}$ be a random sample from a $\Gamma(\alpha, \beta)$ distribution where $\alpha$ is known and $\beta>0$. Determine the likelihood ratio test for $H_{0}: \beta=\beta_{0}$ against $H_{1}: \beta \neq \beta_{0}$
Maximum Likelihood Methods
Maximum Likelihood Tests
Determine the mean and variance of a beta random variable. Use the result that the probability density function integrates to $1 .$ That is, $\frac{\Gamma(\alpha) \Gamma(\beta)}{\Gamma(\alpha+\beta)}=\int_{0}^{1} x^{\alpha-1}(1-x)^{\beta-1}$ for $\alpha>0, \beta>0$
Continuous Random Variables and Probability Distributions
Beta Distribution
The continuous uniform random variable $X$ has density function $$ F(x)=\frac{1}{\beta-\alpha}, \quad \alpha \leq x \leq \beta $$ (a) Show that the moment-generating function is $$ M_{X}(t)=\frac{e^{t \beta}-e^{t \alpha}}{t(\beta-\alpha)} $$ (b) Use $M_{X}(t)$ to find the mean and variance of $X$.
Joint Probability Distributions
Moment-Generating Functions
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD