Consider a uniformly doped silicon npn bipolar transistor at $T=300 \mathrm{~K}$. The device is biased in the forward-active mode with $V_{C B}=2.5 \mathrm{~V}$. The metallurgical base width is $x_{B 0}=1.0 \mu \mathrm{m} .$ The doping concentrations are $N_{E}=8 \times 10^{17} \mathrm{~cm}^{-3}, N_{B}=2 \times 10^{16} \mathrm{~cm}^{-3}$,
and $N_{c}=10^{15} \mathrm{~cm}^{-3} .(a)$ Determine the B-E voltage such that the minority carrier electron concentration, $n_{B}$, at $x=0$ is 10 percent of the majority carrier hole concentration. ( $b$ ) At this bias, determine the minority carrier hole concentration at $x^{\prime}=0$.