00:01
We're going to let brunuli's equation.
00:04
We're going to apply brunle's equation, rather.
00:12
And here we can say that p .1 plus one half row v.
00:17
Sub 1 squared plus row g, h sub 1, plus rather, this would be equal to p sub 2 plus 1 half row v sub 2 squared plus row gh sub 2.
00:35
Here we're going to say that we are applying bernouis equation at the top and the bottom of the wing.
00:46
And so there's not going to be any appreciable height difference.
00:50
So we can eliminate these two terms because of the height difference is going to be very, very small when applying bernoulli's equation at the top and the bottom of the wing.
01:01
And so we can then say that piece of one minus piece of two, the pressure difference.
01:08
Would be equaling to one half times the density of air multiplied by v sub 2 squared minus v sub 1 squared.
01:18
And so this would be equal to the change in pressure.
01:21
And we can say that then finding the velocity sub 2, this would be equal to two times the change in pressure divided by the density row plus v sub 1 squared all to the one half power.
01:37
And for part a, we can solve v .2 would be equaling 2 times 1 ,000 neutons per square meter, divided by the density of air 1 .29 kilograms per cubic meter, plus 60 .0 meters per second quantity squared to the one -half power.
02:09
And so we find v.
02:11
Sub 2 equaling 71 .8 meters per second...