00:01
All right, so we have an electron here, and we have it confined into a diameter of 0 .1 nanometers.
00:11
And we need to figure out what the velocity is and what the classical newtonian energy of it would be without doing relativistic corrections.
00:22
So first thing we want to do is find v.
00:25
Well, we know v is part of momentum, and it says the uncertainty in v is going to be similar to the, actual v.
00:36
So if we know our uncertainty, we'll have a pretty good idea of the b.
00:40
So let's start there.
00:44
So we know that p is equal to mass times velocity, but we are looking for the uncertainty in them because we have a better equation for that.
00:57
So the uncertainty in the momentum is equal to the mass times the uncertainty in the velocity so now we just need to get that velocity.
01:20
So if we plug it into the one equation that we have for uncertainty, the delta x, delta p of x, that's greater than h.
01:37
So plugging this into here, we will get delta x times the mass times delta p is greater than planks constant.
01:59
I'm sorry, not p, that should be v.
02:05
We're putting in for the velocity.
02:10
And then we can find that uncertainty in the velocity by just rearranging a little bit.
02:17
So the uncertainty in the velocity is going to be equal to planck's constant divided by mass times uncertainty in position.
02:31
So now if we take uncertainty in position to be half of our diameter, so one radii, so we're going to say delta x is equal to 0 .5 nanometers, which is equal to 5 times 10 to the negative 11 meters.
02:57
So that's the version we will use...