consider-any-reactions-that-occur-in-exercises-3-and-4-a-write-chemical-equations-b-write-the-net--2

Question

Consider any reactions that occur in Exercises 3 and 4.
a. Write chemical equations.
b. Write the net ionic equation.
c. Identify the more active metal.
d. Which metal is oxidized? Which metal is reduced?

Madi Sousa · Accepted Answer

This is a great practice problem because we get to understand and interpret the reaction for oxidation and its net ionic reaction. And from there we can really understand the definition of oxidation and reduction or redox. So for part A, we know that iron is a less reactive metal than zinc. So what&#x27;s going happen is that the iron nitrate is going to reduce or pardon me. Yes, going to reduce zinc and zinc is going to be oxidized. And so our reaction for this equation is going to look like this, who have three moles of zinc solid and will add two moles of iron nitrate will produce three moles of zinc and nitrite and two moles of solid iron. Now, if we were to write the Net Ionic equation for this, this is what it would look like. We would have two moles of iron three plus, which is acquis, will add three moles of zinc solid, will produce three moles of zinc, two plus acquis and two moles of iron solid. And then, from this Net Ionic equation, we have to ask ourselves well, which is the more reactive metal? Well, zinc is oxidized, much easier than iron. So zinc is the more reactive metal in this Net ionic equation. And then we&#x27;re going to be asking, Well, which metal is being oxidized in which metal is being reduced and this goes back to the definition of Redox. And this is all about the donation and acceptance off electrons. So zinc donates electrons, which means that it&#x27;s going to be oxidized. Iron three plus accepts electrons, which means it&#x27;s going to be reduced. And if you&#x27;re confused about the transfer of electrons, you can simply look at the charges and the Net Ionic equation. For example, zinc went from a neutral charge two a two plus charge, which means that a donated electrons, an iron, went from a three plus charge to neutral, which means it accepted electrons. And that&#x27;s how we got the definition of oxidation and reduction. So I hope that this problem helped you understand how we can write oxidation reactions and then the Net Ionic equation, and then interpret them based on the reactivity of Redox

David Collins · Answer

pass through this list. Balance the Redox reaction. We see that b r 03 minus goes to B R two and br minus also goes to B R. Two. This is sometimes called the disproportion. Ation reaction were the same element that is being oxidized and reduced. You have to, bro means that will add to over here. That then gives us tu minus charge. So we&#x27;re going to need two electrons here going back up to this first half reaction we had to Romanes here. So we need to right here. We now have six oxygen, so going to need six waters. Now we have 12 hydrogen, so we&#x27;re gonna need 12 hydrogen ions. Then we have a total of a 10 plus charge and have it be neutral. Any 10 electron not to make the electrons equal equal where you will need to multiply the second reaction by five and then some them up. Once they&#x27;re summed up, we can see the change in oxidation State for the roaming N b r 03 minus goes from five plus 20 So the answer is is Biaro three minus reduced? Yes. What is the product of B r 03 minus well, Romain water. If we just looking at the 1/2 reaction Is bromide oxidized? Yes, it goes from minus 1 to 0. So it is oxidized for D. What is the product of BR minus? Well, it&#x27;s just the are two.

Tiffany Noble · Answer

All right. So I&#x27;m gonna figure out which dissolves of one more. A gentle three. It&#x27;s right here is my half reaction for a gentle three. I&#x27;m gonna come bear the cell potential for each of them. So for this world, that sell potential of coffer is less than the potential of and 03 So we know it&#x27;s going to be spontaneous for silver for gold. Sorry, E a gold is greater than e of three. So it&#x27;s Bob. Spontaneous. What? And because it&#x27;s a spontaneous now I&#x27;m gonna add those have reactions, right? The balance Redox reaction. So I&#x27;m gonna have this becomes three. See you. Solid plus two and three my

Zhengguo Cai · Answer

showed Who started this react this. To start this question, we first need to know several electoral potentials. The 1st 1 is this species I owe three minus. I die. So these is one point to you is very high, indicating this is a strong Occident. Okay. And the other two we need to know is the mental will be dissolved into the asset. And then they were formed the Ionic forms. And for it&#x27;s a crow me for the gold. The common companies go three plus species. And for the crew me, the common for me is to see our three plus. Okay, if we trap the table, we can see for the gold, this is quite high is 1.5 voltage, but patties in a sterile 0.73 footage. Okay, since this is, um, higher than roaming, but less than the gold, we can say that the gold cannot deserving. Uh, this asset, however, the crow ming could be these up in these absolution. Okay. And for the crew mean the reaction will be Oh, the I 03 minus will be reduced into, um I the our two species and the crew me will be oxidized into crewman three plus. And now I&#x27;ll be some waters. Then we try to, um, Sorry. There should be. We need to balance these. Okay. To penance that what we need to do is just like zis. Okay, so now it is balance. Or you can also times to get rid of this three over two. Um, but yeah, it is a reaction. This is the dissolved the reaction, okay?

Tiffany Noble · Answer

All right. So we&#x27;re gonna figure out how to figure out which one dissolves in one more HD out. So I write the half reactions, and I&#x27;m gonna compare that you cells. So the half fraction of aluminum is they had three plus supposed three life terms, and then the one molar HCL is we&#x27;re going to refer that to the she electrode who&#x27;s dealing with hotch. So you can see that the e the Roomba is less than the E hardin. So the reaction is spontaneous. And now we calculate the, uh, full equation. So okay. Example. In silver. Sylar is a report compared to hydrogen h zero e of a cheese grater. You are so not spontaneous. See? Yeah. Uh, this is less than our zero, so 20 years. So you do the half react, do the right

Ronald Prasad · Answer

Let&#x27;s identify which elements or oxidize in which elements are reduced. For a we&#x27;ve got four and a plus 02 to produce two in a 20 oxidation numbers 00 sodium would be plus one. Oxygen would be minus two sodium. Change in oxidation number This plus one oxygen change in oxidation number. It&#x27;s minus two. Therefore, the sodium is undergoing oxidation. What&#x27;s ready every year. So sodium oxidation in the O to the new growing reduction for me F E plus h two s 04 to produce F e s 04 in each to oxidation numbers. Zero hydration will be plus one oxygen ist minus two will calculate sulfur in a moment plus two minus very minus two for oxygen and zero for the hydrogen. Let&#x27;s calculate sulfur here, um, to hide regions. So, for for oxygen&#x27;s so sweet to plus X minus eight equals zero X is going to be equal to plus six. So so for here, plus six over here we have two plus X minus eight equals zero again, um, we&#x27;re going to have, uh, this be equal to plus six plus six for the sulphur iron. It goes from zero to plus two so the delta o N for iron this plus two and hydrogen is going from +120 The delta o N for hydrogen would be minus one. Therefore, iron is undergoing oxidation each plus it&#x27;s undergoing reduction. Proceed to a l 203 24 e l and 302 oxidation numbers plus three for the aluminum minus two for the oxygen, zero for aluminum, sell it and zero for oxygen is the metal for aluminum changing oxidation number his minus three for oxygenation or oxygen changing oxidation number is uh plus two. Therefore, the aluminum three plus is undergoing reduction in the oxygen to minus. I in is undergoing oxidation. Lastly for D, we have three M G plus and two you produce mg three and two oxidation numbers 00 plus two minus three magnesium delta Oh, in here is going to be plus two for a nitrogen detail to oh in here is going to be minus three. Therefore, magnesium is undergoing oxidation and nitrogen is undergoing reduction

Problem

Platinum is more active than gold but less active…

Problem 5 Easy Difficulty

Consider any reactions that occur in Exercises 3 and 4.
a. Write chemical equations.
b. Write the net ionic equation.
c. Identify the more active metal.
d. Which metal is oxidized? Which metal is reduced?

Answer

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