Consider Exercise 30.
(a) Calculate the probability of at least one match for $n=2,3,4$, and compare it to $1-e^{-1}$.
(b) Show that
$$
\left|1-e^{-1}-\left(1-\frac{1}{2 !}+\frac{1}{3 !}-\cdots+\frac{(-1)^{n-1}}{n !}\right)\right| \leq \frac{1}{(n+1) !} .
$$
Conclude that, for $n \geq 4$, the probability of at least one match differs from $1-e^{-1} \approx 0.63$ by less than 0.01 ; that is, the probability of no match is about 0.63 for all $n \geq 4$.