00:04
So you want to solve this linear system.
00:11
So we have this, and so solving this means we're solving for x, which is going to be a inverse times b.
00:22
So we can rewrite this as the matrix xy.
00:29
It's going to be 2, 4, 3, 5, the inverse of this times for 6.
00:43
Problem 44 tells us that if we have a matrix that's a 2 by 2 matrix we can find its inverse right by doing 1 over k we switch d and a so this becomes d this place becomes a and b and c they change the sign so this negative b is negative c so this is negative c so this is the inverse of 2x2 matrix.
01:19
So we use this idea to find the inverse here.
01:31
So you have one over k.
01:33
So let's see, i just scratchwork.
01:38
K is going to be, yeah, they said k was equal to ad and then minus bc and this should not equal to zero.
01:55
So k is, a is 2, d is 5, minus b is 3.
02:06
This is 10 minus 12, which is negative 2...