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Consider $f:\{1,2,3\} \rightarrow\{a, b, c\}$ given by $f(1)=a, f(2)=b$ and $f(3)=c$. Find $f^{-1}$ and show that $\left(f^{-1}\right)^{-1}=f$.
Algebra
Chapter 1
Relations and Functions
Section 3
Types of Functions
Functions
Campbell University
Oregon State University
Harvey Mudd College
Lectures
01:32
In mathematics, the absolu…
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Let $f(x)=x^{5}+x^{3}+x$
01:46
Let $f(x)=x^{5}+x^{3}+x+3 …
01:49
Given $f(x)=2 x^{2}-3 x,$ …
02:09
Let $f(x)=x^{5}+x^{3}+x-3 …
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Let $f(x)=x^{3}+2 e^{x}$
in this problem of relational concern. The function F is defined from the set 1232 They said 1 to 3 to a B, C, A B and C. And defense. And F one is given by A F. Two is given by B and F. Three is given by six. We have to find F Edwards and also we have to find F inwards and also we have to show that inverse of FN was is equals to have. So first the function F is given way when we are putting one. So this would be so when we are putting one, this was eight, so 18 when we are putting to this is to be and when we are putting three, this is Tracy. So this is different than if and now FN was. So F universe will be given by just opposite of it. So this will be even this, would we be too? And this will we see three. And now when we do the universe of this function, so this will we F. Universe the universe of F inwards. So this will begin interchange. So this will be one A. And this would be to be and that's what we Tracy and when we write it closely, the city equals to have. So we say that this is equals to F. So we see that has proved hands fruit trance, proved what we approved that F inverse of here in verse of half universities equals to have. And this is the value of a fine words. So this is the right answer.
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