00:01
Okay, so starting off with part a, first off, we need to, we know that the researcher evaluated weeds among cornfields in the inquiry.
00:18
And so the computer output of this data is provided.
00:20
So we have y hat is equal to a plus bx.
00:25
And so in the coefficient column of the computer output, the estimates in b are given.
00:31
And so that would be 166 .483 minus 1 .098.
00:37
X and so that's the equation of the least squares regression line for the predicting cornfield and so now we also need to interpret the slope and the y intercept so the slope is b which is negative 1 .0987 and so the y intercept would be a and that is 166 .483 for part b, we need to explain what the value of s means.
01:32
S is equal to sigma, which is equal to standard deviation.
01:42
And then lastly for part c, the following is taken from the computer output.
01:47
So n equals 16b, which is negative 1 .0987, sebs, which is equal to 0 .57.
01:57
And 1 2.
01:59
And so as a result, we define the hypothesis as follows...