00:01
In this problem, we have an atom with angular momentum quantum number l, which is equal to 2.
00:07
So here for part a, now if l is just equal to 2, so now if l is equal to 2, so now fl is equal to 2, so now m -sup l, which is the quantum number of the z component of the angular momentum, is just equal to minus 2 or minus 1 or 0 or 1 or 2.
00:36
So now the maximum value of l sub z, which is the z component of the angular momentum is just equal to m sub l multiplied by h par at maximum.
01:04
Because the value of l sub z just equal to n -sup l times h -par and this is equal to 2 h -part.
01:14
This is for part a.
01:16
Now for part b, l, the value of the angular momentum just equal to h -par multiplied by the square root of l times l plus 1.
01:35
And here, l just equal to 2.
01:38
So now little l is just equal to 2 so a big l is just equal to hpar times root 6 so from here l is just greater than l z this is for part b now for part c we know that l cosine and here theta is the angle between the angular momentum vector and the z axis.
02:15
So here l cosine of theta just equal to lz.
02:22
So cosine of phi is just equal to lz divided by l.
02:32
And now, phi is just equal to cosine inverse of lz divided by l...