00:01
Problem number two, we are considering states that have an l value of 3, and for part a in units of h -bar, what is the largest possible value of lz? well, if lz is defined as such, then we want to maximize this, and that is going to be max, of course, at plus l.
00:29
So the maximum value for l equals 3 is simply going to be plus 3h bar.
00:40
Easy enough, but on to b, we want to find the value of l, and which is larger, the big l value or the maximum possible l.
00:53
Z.
00:56
Well, l is given here, and we see that it is two.
01:08
Thirds or sorry two thirds two square root three times h bar and this is of course larger than this and in fact l will always be larger than l z because l z is just a component of l and finally for part c we are we'll give it a little splash of color uh we are to assume a model where our l vector is described classically, and we want to know for each possible value of lz, what angle does that vector make with the axis? well, given that, we can say cosine theta is going to be equal to lz over l, that's just a geometric considerations, then we can sort of piece together some stuff.
02:21
So there are going to be some allowed values depending on what this lz is, because it depends on ml.
02:40
Thus, we have to sort of walk through them all and find a expression for the angle.
02:51
So i'm going to go ahead and derive this.
02:56
So we'll say our theta is equal to inverse cosine of lz over l, which is just inverse cosine of mlh bar, all on ll plus 1h bar.
03:24
And now we have a nice simple expression that only depends on ml and l.
03:31
And since l doesn't change for this case, we'll go to a new page and write out our magnum opus for part c.
03:41
Our theta is just going to depend on ml, all on 2, root 3, and that's it.
04:01
In ml goes from 0, positive minus 1, positive minus 2, and since we are going up to l equals 3, positive minus 3, positive minus three...