00:01
We can write the velocity profile u is equal to g sine theta divided by nu multiplied by hy minus y square divided by 2.
00:17
Let this equation be equation number 1.
00:20
From here we get the kinematic viscosity.
00:24
New can be written as g sine theta, g sine theta divided by u multiplied by h y minus y squared divided by two now as we know the velocity will be maximum at y is equal to h by two so at y is equal to h by two we have we have u is equal to u max hence our viscosity term mu will be equal to g sine theta divided 2 u max multiplied by h squared by h squared so this will be at y is equal to h the velocity will be maximum at y is equals to h not h by 2 velocity will be max at at y is equals to h so upon putting this value in equation 1 we get new is equal to g so let's put the values of here.
01:29
So g is 9 .81 multiplied by sine 30, xx0.
01:38
Multiplied by the value of h square h is 0 .8 multiplied by 10 to the power of minus 3 meter this square divided by 2 multiplied by u maxes 15 .7 multiplied by 10 to the power of minus 3 15.
01:59
7 multiplied by 10 to the power of minus 3.
02:02
From here we get kinematic viscosity new is equal to 1 multiplied by 10 to the power of minus 5 meter square per second.
02:13
So this is the kinematic viscosity of the liquid given in our problem.
02:24
Now in order to plot the velocity profile, we need to assume some value for y by h and tabulate the values for u by u max.
02:32
So we will write u divided u max u divided by u x is equal to g sine theta divided by new multiplied by divided by u max for u max it is g sine theta multiplied by h squared divided by two new multiplied by h y minus y squared divided by two or upon further solving we can write u.
03:02
Divided by u max is equal to 2 divided by h squared multiplied by h y minus y square divided by 2 so from here we can write u divided by u max is equal to 2 multiplied by y divided by h minus y divided by h whole square let this equation be equation number three now we will form it table so let's form the table so let's put y by h and let's calculate let us calculate the value of u by u max so let us put the values so at y by h equal to zero we have u by u max at y by h equal 0 .2 we have u by u max is got to 0 .36.
04:08
At y by h.
04:09
Is equal to 0 .4, we have u by u max jumped to 0 .6 4.
04:14
At y by h is equal to 0 .6, we have u by u max going to 0 .8 4...