Question
Consider the chemical reaction:$$2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)$$How many moles of $\mathrm{H}_{2} \mathrm{O}$ are required to form $1.3 \mathrm{L}$ of $\mathrm{O}_{2}$ at $325 \mathrm{K}$ and 0.988 atm?
Step 1
3 L under the given conditions. We can do this using the ideal gas law, which is given by $PV = nRT$, where $P$ is the pressure, $V$ is the volume, $n$ is the number of moles, $R$ is the gas constant, and $T$ is the temperature. Show more…
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