Consider the circles
$C_{1} \equiv x^{2}+y^{2}-4 x+6 y-2=0$
$C_{2} \equiv x^{2}+y^{2}+9 x+6 y-2=0$
Statement 1
The centre of the circle passing through the intersection of the circles $\mathrm{C}_{1}=0$ and $\mathrm{C}_{2}=0$ and through the point $(1,1)$
lies on the line $3 x+y=0$
and
Statement 2 Any circle through the intersection of $\mathrm{C}_{1}=0$ and $\mathrm{C}_{2}=0$ can be written as $\mathrm{C}_{1}+\lambda \mathrm{C}_{2}=0$ where, $\lambda$ is a constant.