Question
Consider the circuit in Figure P19.48. The resistors are identical with $R_{1}=R_{2}=R_{3}=2000 \Omega$ and the battery voltage is $\varepsilon_{1}=9.0 \mathrm{V}$. What is the current through resistor $R_{1} ?$
Step 1
Since they are in parallel, we use the formula for parallel resistors: \[R_{P} = \frac{R_{2} \cdot R_{3}}{R_{2} + R_{3}}\] Substituting the given values, we get: \[R_{P} = \frac{2000 \Omega \cdot 2000 \Omega}{2000 \Omega + 2000 \Omega} = 1000 \Omega\] Show more…
Show all steps
Your feedback will help us improve your experience
Varsha Aggarwal and 93 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
$*$ Determine (a) the equivalent resistance of resistors $R_{1}, R_{2},$ and $R_{3}$ in Figure $\mathbf{P} 16.32$ for $R_{1}=28 \Omega, R_{2}=30 \Omega$ and $R_{3}=20 \Omega$ and (b) the current through the battery if $\varepsilon=10 \mathrm{V}$
Assume the resistance values are $R_{1}=2400 \Omega, R_{2}=1400 \Omega, R_{3}=4500 \Omega,$ and $R_{4}=6000 \Omega,$ and the battery emfs are $\varepsilon_{1}=1.5 \mathrm{V}$ and $\varepsilon_{2}=3.0 \mathrm{V},$ unless stated otherwise. Use your results from Problem 50 to find the current through $R_{2}$ in Figure P19.48. Hint: First find the voltage across the parallel combination of resistors.
Electric Currents and Circuits
DC Circuits: Batteries, Resistors, and Kirchhoff’s Rules
Consider the circuit in Figure $\mathrm{P} 19.22$ with resistors $R_{1}=3200 \Omega$ and $R_{2}=8100 \Omega$, and batteries with emfs $\varepsilon_{1}=7.5 \mathrm{V}$ and $\varepsilon_{2}=2.3 \mathrm{V} .$ What is the magnitude of the current in the circuit?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD