00:01
For this question, the first part of the question we want to find the unknown currents.
00:09
The first step we can do is to look at loops that involve as small number of unknowns as possible.
00:18
So one of the loops is over here.
00:21
So in this loop, there's the only unknown that will be involved is i4.
00:27
And writing down the kerchoff's loop rule, we start off with the battery moving from minus to positive.
00:35
Add that v2 so this is 5 volts then we bypass r4 in the same direction as the current so we subtract away the potential drop so that's 2 om times i4 and we create this to 0 so you can find i4 to be 2 .5 ampiers all right next we will need four other equations to find the for other unknowns to i5.
01:14
So the first equation i'm going to use the junction, junction rules, where the incoming current must be equal to the outgoing current.
01:27
So for the first junction on the right we have i4 as the incoming current and the outgoing will be i5 and i3.
01:37
For the second junction, i3 and i1 are incoming and i2.
01:45
Is the only outgoing current.
01:55
The third equation we're going to use the different loop rules.
02:00
So a second loop we can look at is over here and for this loop we start off with the battery again.
02:13
So we are moving from positive to negative so we got a minus away v2 so that's minus 5 then we bypass r3 same direction as the current so minus 2 times i3 then we bypass r1 in the opposite direction so we plus equate this to 0 the last equation that we'll need is over here this particular loop we start off the battery from minus to plus so we add v1 let's jump bypass r1 minus 4 times of i1 then we bypass i2 which is also subtract because it's in the same direction as the current.
03:13
So let me 3 times i2 goes to 0...