00:01
For this problem on the topic of inductance, we are shown an rl circuit in the figure, and we are told that the switch in this circuit is closed at t is equal to zero.
00:10
We want to find the current in the inductor and the current through the switch as functions of time thereafter.
00:17
Now, we'll name the currents i1, i2, and i3 as shown in the circuit diagram, and then we can use kershaw's laws, and the first of which tells us that i1 is equal to the current i2, plus the current i3.
00:34
Next, we have that positive 10 volts minus 4 times current i1, minus 4 times i2, since both resistors are 4 oms, is equal to 0.
00:57
And then 10 volts minus 4 times i1 minus 8 times i3 minus 1 times di3 times di3 d i3 d t through the inductor is also equal to 0 so we have three equations that we can use now from equations 1 and 2 we have the following we have positive 10 minus 4 i1 minus 4 i1 plus 4 i3 is equal to 0.
02:07
And the current i1 is equal to 0 .5 i3 plus 1 .25 ampiers...